We can use these values to calculate the solubility product constant ($K_{sp}$) at each temperature. The reaction for the dissolution of $\mathrm{PbI}_{2}$ is:
$$\mathrm{PbI}_{2}(s) \longrightarrow \mathrm{Pb}^{2+}(a q)+2 \mathrm{I}^{-}(a q)$$
So, $K_{sp} =
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