00:01
Question 62 is a ksp and molar solubility question with various parts.
00:09
It always helps with these types of questions that we write the ksp equilibrium expression.
00:16
In this case, it would be m2x going to 2m pluses and 1x2 -minus.
00:23
The ksp expression would be m plus squared because of the coefficient 2, multiplied by the x2 minus concentration.
00:34
The molarity of the m plus concentration will be equal to two times molar solubility because every time one mole of the solid dissolves, we get two moles of the ion m plus.
00:48
However, the concentration of x will simply be equal to molar solubility because every time one mole of the solid dissolves, we get one mole x2 minus.
00:58
So knowing molar solubility we can solve for the concentration of m plus, it will simply be two times molar solubility or 1 .0 times 10 to the negative 4, while the x2 minus concentration will simply be equal to molar solubility or 5 times 10 to the negative 5.
01:18
The ksp expression then can be written as we did before and substituting in 2s for m plus and s for x2 minus...