00:02
All right, so we have a certain gas that has a specific heat at constant pressure, which is given to us looks like this.
00:09
There's a constant term.
00:10
There is a linear term, and then there's a quadratic term.
00:15
And we're asked to calculate the entropy as this gas goes from 20 degrees celsius to 200 degrees celsius.
00:24
So our initial temperature in kelvin is going to be 293 kelvin.
00:33
Our final temperature is going to be 473 kelvin.
00:39
So our change in entropy then is the integral of, let's see, i'm sorry, i think we have two moles of this gas, i should say that.
00:47
So we have two moles.
00:50
So our entropy is going to be the integral of dq over t from this first temperature to 93 to 473.
01:00
So let's start substituting in some of these things...