Question
The Moon has no atmosphere, making extremely low orbits possible. Find the period of a circular orbit just above the Moon's surface $\left(M_{\text {Moon }}=7.35 \times 10^{22} \mathrm{~kg}, R_{\text {Moon }}=1740 \mathrm{~km}\right)$
Step 1
This can be written as: \[T^2 = \frac{4\pi^2R^3}{GM}\] where \(T\) is the period of the orbit, \(R\) is the radius of the orbit, \(G\) is the gravitational constant, and \(M\) is the mass of the central body (in this case, the Moon). Show more…
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