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The Moon's mass is $7.34 \times 10^{22} \mathrm{kg},$ and it is $3.8 \times 10^{8} \mathrm{m}$ away from Earth. Earth's mass is $5.97 \times 10^{24} \mathrm{kg}.$a. Calculate the gravitational force of attraction between Earth and the Moon.b. Find Earth's gravitational field at the Moon.

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Physics 101 Mechanics

Chapter 7

Gravitation

Section 2

Using the Law of Universal Gravitation

Dynamics of Rotational Motion

Rutgers, The State University of New Jersey

University of Washington

Simon Fraser University

University of Sheffield

Lectures

03:55

In physics, orbital motion is the motion of an object around another object, which is often a star or planet. Orbital motion is affected by the gravity of the central object, as well as by the resistance of deep space (which is negligible at the distances of most orbits in the Solar System).

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

02:16

Find the gravitational for…

03:28

"Find the gravitation…

04:10

Mass of the earth is 6 × 1…

03:26

01:22

Gravitational Field The ma…

00:25

Mass of moon is $7.34 \tim…

00:41

03:39

The mass of the earth is $…

01:24

Calculate the force of gra…

01:41

The Moon, whose mass is $7…

02:28

02:54

01:56

The force with which the e…

01:01

The ratio of the mass of t…

06:23

The distance between the e…

03:24

The mass of the Earth is $…

03:03

The masses of the Moon and…

In the first part of this problem, we have to calculate the force of gravitation between moon and earth so that this force is now using neutrons log gravitation. We can define the force of attraction between moon and, as f, equals to g m e m m divided by r square. We call it equation number 1 here this is the gravitation constant, is the man of heart and in the mass of moon, where they, this r, in the distance from center of earth to the center of moon. Now, by inserting values into the square, we can write. F, equals to 6.67 multiplied by 10 as power minus 11 newton meter square per kg square into the mancos 5.97 multiplied by 10 as power 24 kg and the mesomoon is 7.34 multiplied by 10 as power 22. So this will be divided divided by 3.8 multiplied by 10, raise power. 8 meter whole square, so this will give us the value for this f, a f equals to 2.0 multiply by the wise power 20 neterso. This is the answer or first part of this problem. In second part of this problem, we have to calculate the earth's gravitation field when this field is a g e. So we can write a relation for this as a g equals of divided by m, where his is the mass of the moon. Now, when setting wells into this question, we can write this g equals to 2.0 multiplied by 10, as power 20 newton divided by 7.34, multiplied by 10. It power 22 catching. So this will give us a value for this g. A g equals to 0.0027 newtonso. This is the answer or second part, of this problem. Thank you.

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