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Two 1.00 -kg masses have their centers $1.00 \mat…

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Problem 74 Hard Difficulty

The Moon's mass is $7.34 \times 10^{22} \mathrm{kg},$ and it is $3.8 \times 10^{8} \mathrm{m}$ away from Earth. Earth's mass is $5.97 \times 10^{24} \mathrm{kg}.$
a. Calculate the gravitational force of attraction between Earth and the Moon.
b. Find Earth's gravitational field at the Moon.


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Related Courses

Physics 101 Mechanics

Physics Principle and Problems

Chapter 7

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Section 2

Using the Law of Universal Gravitation

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Video Transcript

In the first part of this problem, we have to calculate the force of gravitation between moon and earth so that this force is now using neutrons log gravitation. We can define the force of attraction between moon and, as f, equals to g m e m m divided by r square. We call it equation number 1 here this is the gravitation constant, is the man of heart and in the mass of moon, where they, this r, in the distance from center of earth to the center of moon. Now, by inserting values into the square, we can write. F, equals to 6.67 multiplied by 10 as power minus 11 newton meter square per kg square into the mancos 5.97 multiplied by 10 as power 24 kg and the mesomoon is 7.34 multiplied by 10 as power 22. So this will be divided divided by 3.8 multiplied by 10, raise power. 8 meter whole square, so this will give us the value for this f, a f equals to 2.0 multiply by the wise power 20 neterso. This is the answer or first part of this problem. In second part of this problem, we have to calculate the earth's gravitation field when this field is a g e. So we can write a relation for this as a g equals of divided by m, where his is the mass of the moon. Now, when setting wells into this question, we can write this g equals to 2.0 multiplied by 10, as power 20 newton divided by 7.34, multiplied by 10. It power 22 catching. So this will give us a value for this g. A g equals to 0.0027 newtonso. This is the answer or second part, of this problem. Thank you.

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