00:01
Problem 91 says that some molecules can disobey the octet rule when central atoms can have more than eight electrons.
00:11
So these are sort of a special case, and they follow the same general rules of drawing lewis structures, but keep in mind that the central atom can, in fact, sort of be an exception to the octet rule.
00:25
So for pf5 here, phosphorus has five valence electrons and fluorine has seven each, so making the total valence contribution from fluorine 35.
00:46
In that case, we're looking for a total of 40 valence electrons.
00:52
So we can draw the central atom here, phosphorus, and n.
00:58
To that we'll draw five fluorines.
01:09
So already we have two, four, six, eight, ten electrons.
01:16
We can start by filling in the valence electrons for fluorine to account for the rest.
01:32
And so right now, because we have five fluorines bound to the central phosphorus, each of them being surrounded by eight electrons, we have a total of 40, which is what we wanted.
01:45
But here you'll see that the central phosphorus is surrounded not by 8, but by 10 electrons.
01:54
Now the question asks us why some of the atoms on the periodic table can do this.
02:00
And the answer is, if you look at where phosphorus falls on the periodic table, you'll see that at that point of the table and below, d -orbital's open.
02:16
And so what can happen with elements like phosphorus is even though, you know, in theory, they should only have eight electrons surrounding them, the extra electrons that come from making more bonds than you might expect can go to these empty d orbitals that are relatively close in energy to s &p orbitals.
02:38
Smaller atoms like, you know, say oxygen can't do this.
02:49
So we can move on to sf4.
02:52
Again, we have a central sulfur down to four fluorines.
03:00
So for sulfur, we are in general looking for six valence electrons, and with four fluorines, that's 28...