The most important commercial ore of chromium is chromite (FeCr2 O4) One of the steps in the pro

Name: Problem 50, Chapter 11: Chemistry Matter and Change
Uploaded: 2020-06-08T00:13:29-08:00
Duration: 1 min 25 s
Channel: Chance Lander
Description: The most important commercial ore of chromium is chromite (FeCr2 O4) One of the steps in the process used to extract chromium from the ore is the reaction of chromite with coke (carbon) to produce ferrochrome (FeCr2) 2 C(s)+Fe Cr2 O4(s) →FeCr2(s)+2 CO2(g) What mole ratio would you use to convert from moles of chromite to moles of ferrochrome?

step 1 If we want to know how many moles of ferrochrome we can make, from a certain number of moles of

Question

The most important commercial ore of chromium is chromite $\left(\mathrm{FeCr}_{2} \mathrm{O}_{4}\right)$ One of the steps in the process used to extract chromium from the ore is the reaction of chromite with coke (carbon) to produce ferrochrome $\left(\mathrm{FeCr}_{2}\right)$ $$2 \mathrm{C}(\mathrm{s})+\mathrm{Fe} \mathrm{Cr}_{2} \mathrm{O}_{4}(\mathrm{s}) \rightarrow \mathrm{FeCr}_{2}(\mathrm{s})+2 \mathrm{CO}_{2}(\mathrm{g})$$ What mole ratio would you use to convert from moles of chromite to moles of ferrochrome?

   The most important commercial ore of chromium is chromite $\left(\mathrm{FeCr}_{2} \mathrm{O}_{4}\right)$ One of the steps in the process used to extract chromium from the ore is the
reaction of chromite with coke (carbon) to produce ferrochrome $\left(\mathrm{FeCr}_{2}\right)$
$$2 \mathrm{C}(\mathrm{s})+\mathrm{Fe} \mathrm{Cr}_{2} \mathrm{O}_{4}(\mathrm{s}) \rightarrow \mathrm{FeCr}_{2}(\mathrm{s})+2 \mathrm{CO}_{2}(\mathrm{g})$$
What mole ratio would you use to convert from moles of chromite to moles of ferrochrome?

Chemistry Matter and Change

Thandi Buthelezi,… 1st Edition

Chapter 11, Problem 50

Instant Answer

Solved by Expert Chance Lander

06/08/2020

Step 1

This means that the number of atoms of each element on the reactant side (left) should be equal to the number of atoms of each element on the product side (right). Show more…

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The most important commercial ore of chromium is chromite $\left(\mathrm{FeCr}_{2} \mathrm{O}_{4}\right)$ One of the steps in the process used to extract chromium from the ore is the reaction of chromite with coke (carbon) to produce ferrochrome $\left(\mathrm{FeCr}_{2}\right)$ $$2 \mathrm{C}(\mathrm{s})+\mathrm{Fe} \mathrm{Cr}_{2} \mathrm{O}_{4}(\mathrm{s}) \rightarrow \mathrm{FeCr}_{2}(\mathrm{s})+2 \mathrm{CO}_{2}(\mathrm{g})$$ What mole ratio would you use to convert from moles of chromite to moles of ferrochrome?

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Key Concepts

Stoichiometry

Stoichiometry is the study of the quantitative relationships between the amounts of reactants and products in a chemical reaction. It uses the coefficients from a balanced chemical equation to determine how many moles of one substance react with or produce a specific number of moles of another substance.

Mole Ratio

The mole ratio is the ratio of the coefficients of any two substances in a balanced chemical equation. It is used to convert between moles of different substances within the same reaction. In the given reaction, the mole ratio of chromite to ferrochrome is 1:1, meaning one mole of chromite produces one mole of ferrochrome.

Balanced Chemical Equation

A balanced chemical equation accurately represents the conservation of mass during a reaction. Each reactant and product is represented with the correct coefficient, which is essential for performing stoichiometric calculations and determining mole ratios.

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