00:01
So firstly, we'll calculate the wavelength lambda for the low node.
00:08
Lambda l is equal to the speed of sound in a, v, over the frequency of the node f.
00:17
The speed of sound is 343 meters per second, and the frequency of the note is 146 .8 hertz, or 146 .8 per second.
00:33
And this gives us the wavelength of the no note to be 2 .34 meters.
00:43
The wavelength of the high note we get from the same formula v over f with a frequency now changing.
00:52
So the speed of the wave stays unchanged, it's the speed of sound in a but the frequency of the high node is 880 hertz or 880 a second.
01:05
Hence we get the wavelength of the high note to be 0 .3 .9 meters.
01:19
Next for part b, we are given the sound level, and the sound level we know is defined as 10 decibels multiplied by the log of the intensity of a sound i, which we wish to find, divided by the reference intensity 10 to the minus 12.
01:47
Watts per square meter and we're given the sound level to be 75 decibels so if we rearrange this equation we can find the intensity i and if we rearrange us we see that i is equal to 3 .16 times 10 the minus 5 watts a square meter now that we have i we can calculate the pressure amplitude since we know that i is defined as the pressure amplitude delta p max squared over two times the density of the medium in which the wave travels times the speed of the wave so if you rearrange this we can find the pressure amplitude as required so the delta p max is simply the square root of i times 2 row v so that's the square root we just calculated the intensity to be 3 .16 times 10 to the minus 5 watts per square meter so it's addressed the units multiplied by 2 and the density of a which is 1 .2 kg per cubic meter and the speed of sound in a 3003 meters per second during the calculation we get the pressure amplitude to be 0 .161 pass curve and note that this pressure amplitude is for both the low and the high notes...