00:01
This question is asking us about a circular saw, which is connected by a belt to a motor, which is spinning at an angular velocity of 3 ,450 revolutions per minute.
00:15
The pulley that is attached to the motor is two times the radius of the pulley attached to the saw.
00:25
And the radius of the saw itself attached to the second pulley is 0 .104 meters.
00:36
And so given all this, a is first asking us to calculate the tangential velocity of a point at the edge of the saw.
00:46
So the first thing to do here is to convert these revolutions per minute into radians per second so the way to do that just use our conversion factors equals 3450 revolutions per minute and if i multiply that by pi over 30 i will get my radians per second of 361.
01:52
And now to find the angular velocity of the saw, all we need to do is compare these two pulleys.
01:59
Now since r1 is double the size of r2, we know that the circumference of the first pulley is also double that of the second.
02:12
So every rotation it makes, they'll be pulling the pulley around twice, because that distance is being conserved by the belt.
02:22
So we know then that at the same time, the velocity is the same, but because the radius is halved, the angular velocity will be doubled.
02:34
So we know that the angular velocity of the saw will be double this, or 7202 radians per second...