00:01
Okay, this is a pretty interesting question, right? so why is it that the, if you look at that range of electron withdrawing groups on your, in the chapter that introduces substituent effects, you'll notice that there's something more deactivating than the nitro group, and that's the trimethoammonium or really any type of alcohol ammonium.
00:25
So that is when nitrogen has a fourth bond to carbon.
00:30
So its lone pair electrons are being taken.
00:38
And so the loan payer is gone, is what i'm trying to say.
00:41
They're involved in a bond that really cannot be broken easily, a nitrogen carbon bond.
00:46
So now there's a formal positive charge on nitrogen.
00:49
So because of that, we can't do resonance anymore in the ring, right? so first of all, resonance requires that you have, um, electrons to push, right? i can't, because there's no loan pair anymore, i don't have a lone pair to push down into the ring, which is why we can show through residents that amino groups, for example, are electron donating.
01:18
That's for starters.
01:20
There's also no way that we can do this, because if there was some carbonyon, we were cycling in the ring, there is no way we could push the pie bonds up because, one, there's no vacant p orbital, right? so residence also requires things to be flat.
01:39
So there's no orbital for the nitrogen to accept those electrons into, but also we've been making five bonds to nitrogen, which is illegal.
01:48
Then it would have 10 valence electrons, which is not possible, right? so that's the resonance argument.
01:56
What about just think about the kind of reaction.
02:00
That i've drawn at the top here, right? so think about what happens if you were going to add something to this ring.
02:07
So this notation where you have the substituent coming out of the center of the ring just means that it's a general, it's a vague general scheme for that electron could be anywhere.
02:18
That electron, sorry, that substituent can be anywhere.
02:20
That electrofile can be at any position on that ring.
02:23
It doesn't matter where, for the sake of the scheme that it's in, you just have two substituents and that e is at whatever position with respect to the triatholomino group, triathill ammonium, sorry.
02:36
So we're going to draw the orthometro and para resident structures with upon addition of a second substituent to the benzene ring.
02:49
Right? so i'm going to make the ortho ones appear here.
02:53
There we go.
02:54
So you'll notice that if we start so if we add the electrophile to the ring right here and we start pushing the electrons around, we're going to get to an intermediate that puts both of those the carbocadion on the same atom as the nitrogen that also has a positive charge.
03:15
So when in chemistry have you seen two formal positive charges next to each other and have that be low energy? right...