The $n$ th root of $n !$
a. Show that $\lim _{n \rightarrow \infty}(2 n \pi)^{1 /(2 n)}=1$ and hence, using Stirling's
approximation (Chapter 8 , Additional Exercise 32 $\mathrm{a}$ , that
$\sqrt[n]{n !} \approx \frac{n}{a}$ for large values of $n$
b. Test the approximation in part (a) for $n=40,50,60, \ldots,$ as far as vour calculator will allow.