00:01
In this question, we are asked to determine an expression for the bonding energy e0 of two adjacent ions, and we are provided instructions on how to do this.
00:15
So step one is to differentiate the given expression, which happens to be equation 2 .11 that was referenced later in the question.
00:28
So we're going to differentiate with respect to r, this expression, negative a over r plus b over r to the n.
00:38
I find it helpful to go ahead and write this as negative a times r to the negative 1 plus b times r to the negative n.
00:52
And so that makes it easier to see that when we differentiate, we will take the coefficient negative a times the exponent negative one times r to the negative second because we decrease our exponent by one.
01:10
Plus again our coefficient b times our exponent negative n times r to the negative n minus 1 because we decrease our exponent by 1 and so this gives me a times r to the negative second second minus b times n times r to the negative quantity n plus one.
01:42
And so if we go ahead and write this in like a regular format, we'll have a over r squared minus b times n over r to the n plus 1 and the second step that we are given is to set this coefficient or sorry a derivative equal to 0 because of course finding the minimum of a function which is going to represent our bonding energy in this case is found by finding the derivative and setting it equal to 0 so we will be able to add that b n over over r to the n plus one term to both sides.
02:33
And so now i'm going to collect all of my r terms on the same side.
02:38
So i'm going to multiply both sides by r squared and then divide both sides by b times n.
02:48
And remembering my rules for coefficients...