The no-bias transition capacitance of a silicon diode is 8 pF with VK=0.7 V and n=1 / 2. What i

step 1 In this question we have to find the reverse bias saturated current and a forward bias current f

The no-bias transition capacitance of a silicon diode is 8...

The no-bias transition capacitance of a silicon diode is $8 \mathrm{pF}$ with $V_{K}=0.7 \mathrm{~V}$ and $n=1 / 2$. What is the transition capacitance if the applied reverse bias potential is $5 \mathrm{~V}$ ?

Key Concepts

Junction Capacitance

Junction capacitance refers to the capacitance associated with the depletion region of a p–n junction. It represents how the diode stores charge across its depletion layer and varies with changes in the applied voltage.

Depletion Region

The depletion region is a zone at the p–n junction that lacks free charge carriers, where immobile dopant ions create an electric field. The width of this region changes with applied reverse bias, impacting the overall capacitance of the diode.

Reverse Bias

Reverse bias is the application of a voltage in the direction that widens the depletion region in a semiconductor junction. This increased width results in a reduction of the junction capacitance, following a specific voltage-dependent relationship.

Built-in Potential

The built-in potential is the inherent voltage present across a p–n junction due to the difference in doping concentrations of the two regions. It plays a critical role in determining the behavior of the depletion layer and consequently the junction capacitance.

Grading Coefficient (n)

The grading coefficient 'n' is an exponent in the capacitance-voltage relationship that reflects the nature of the doping profile across the junction. For a step or abrupt junction, n is typically 1/2, and it directly influences how the capacitance decreases with increasing reverse bias.

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