00:01
So in this problem, we need to show that if two persons and they're separated by the distance of one arm, which is on average 0 .5 meters, if one person had just 1 % more electrons than protons, compared to another person that can be assumed to be neutral, then the force of repulsion will be so strong that it will be equal to the gravitational force of the earth fg.
00:31
So first we see how many protons there are in human body.
00:39
And knowing that human body mostly consists of the water molecules, we can assume that whole body of a human being is like a body of water, and the number of protons is we should divide the other, some average weight of a protein.
01:06
Person, which is, for example, 80 kilograms, we should divide that by the molar mass of the water and then multiply that by molecules per mole number and then multiply that by protons per molecule number.
01:23
And in this case, water has 10 protons per molecules.
01:29
So we can write 80 kilograms over 0 .018 kilograms per moles.
01:40
So this is the molar mass of the water times the number which states how many molecules are there per one mole on the water times 10 protons per molecule.
02:15
And this equals to 2 .68 times 10 to 28 protons.
02:21
So the charge is then, this is the positive charge in this case number of protons times e or the fundamental charge.
02:37
This equals to the 10 to the negative 19 columns which is equal to 4 .29 times 10 to the 9 power columns.
03:09
So this, this here, this quantity of charge, then we need to find what is 1 % of this.
03:22
So this would be quantity of charge if we had a completely charged person...