Question
The normal at the point $(1,1)$ on the curve $2 y+x^{2}=3$ is(A) $x+y=0$(B) $x-y=0$(C) $x+y+1=0$(D) $x-y=1$
Step 1
The derivative will give us the slope of the tangent line at any point on the curve. The equation of the curve is $2y + x^{2} = 3$. Differentiating both sides with respect to $x$, we get \[2 \frac{dy}{dx} + 2x = 0.\] Show more…
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