00:01
In this problem, we are to consider a solution in ethanol.
00:07
The normal boiling point of ethanol is 78 .4 degrees celsius.
00:19
When 3 .26 grams of a soluble non -electrolite, that means it'll all dissolve in an ethanol, is dissolved in 100 grams of ethanol.
00:43
I'm going to abbreviate ethanol, etoh.
00:50
At that temperature, at 78 .4 degrees, so at the temperature, the boiling point.
00:56
The vapor pressure of the solution is 100 kilopascals.
01:08
What is the molar mass of the solute? okay, so this isn't too tough to do.
01:25
It will take a little time and i hope i've got it done right here.
01:28
Let's begin.
01:31
Make sure i've got everything down.
01:36
First of all, let's find the mole fraction of the solute.
01:47
Let's start up here.
01:51
Mole fraction of the solute.
01:56
We're going to find that by our pressure is going to be equal to the mole fraction.
02:16
I'm just looking here times the pressure of our solvent.
02:21
Now since we're at the boiling point, a pressure of our solvent is going to be 101 .3 kilopascals.
02:29
This was going to be 100 kilopascals equals our mole fraction.
02:42
Solving for mole fraction, i got 0 .01.
02:49
0128.
02:51
Wait, that wasn't quite right here.
02:57
I forgot to do something.
03:04
For this, i took 101 .3 minus 100.
03:12
There we go.
03:13
And those are caskof kilopascals.
03:15
Then, solving for the solute.
03:21
I got 0 .0128.
03:28
Okay, that was my first step.
03:34
Make sure i've got this here...