0:00
Hi there.
00:01
So for this problem, we are told that the nuclei of borough and carbon are saying to be pair of mirror nuclei because they have the same number of nucleons.
00:13
And the number of protons in one equals the number of neutrons in the other.
00:19
If nuclear forces are charged independent, their total binding energies should differ only in that the column energy is higher, in carbon 611.
00:33
Now the atomic mass of 5 borough 11 is given and that it has a value of 11 .0 .0 .0 .93 .0 units of mass.
00:57
And in the case of 6 carbon 11 .11.
01:04
Its math is 11 .011432 units of mass.
01:15
Now for part a of this problem we are asked to evaluate the difference in their total biting energies.
01:25
So to obtain this we do this following procedure.
01:29
We know that the divided energy for borough is equal to five times the mass of hydrogen plus six times the mass of a neutron and this minus the mass of borough and this times the speed of light to the square.
01:53
Now we just simply substitute all of these values.
02:00
So in here we're going to obtain the following.
02:05
The sum of these two terms in here give us a value of 11 .091, 118.
02:22
And this minus the mass of borough, which is 11 .009, 305.
02:32
And this times the speed of light to the square.
02:34
We know that the speed of light is 931 .5 megalletron bolts.
02:41
So with this, we will have that the energy of borough is equal to 76 .209 mega electron balls...