00:01
So we will be assuming that the difference we're going to have is officer d minus m.
00:07
That's the way i'm going to subtract.
00:08
We could go the other way, but we'll just do it in that order.
00:11
We're assuming that that difference is zero, and alternately, that the difference is not zero.
00:17
So we want to show a two -tail test in this case.
00:20
And i have the differences as four, three, five, four, and seven.
00:26
So we only have a sample size of five, not a lot.
00:30
And when we do our calculation for this particular test, and we get that the mean and standard deviation of that data, the mean is 4 .6 citations, and the standard deviation is 1 .516, and i'll call it 6.
00:53
And so we will be assuming we're using a 5 % significance level.
01:00
And so let's draw a little picture here.
01:03
We're assuming that the mean difference is equal to zero for that sampling distribution of sample sizes of five.
01:11
And since we're doing a two -tail test, we're going to have our values with the 0 .025 in each tail.
01:21
And this is where we would reject the null down here and also down here with that tail being the lower tail being 0 .025.
01:30
And we would reject the null down here.
01:32
And so we need to find the t value with four degrees of freedom that has that 2 .5 % in the upper tail.
01:39
And that value is 2 .776.
01:44
So anything higher, greater than or equal to that, we would reject the null and anything less than are equal to negative 2 .76...