00:01
So we're assuming that the proportion 1 is less than or equal to proportion 2.
00:07
And alternately, that proportion 1 is greater than proportion 2.
00:12
So we're doing a 1 -tel test.
00:14
And we have our first proportion being that 70 out of 100.
00:20
And our second proportion is the 90 out of 150.
00:26
And question a asks us to determine what our decision rule, and we're using a 5 % significance level with one tail.
00:36
So we're going to put all 5 % in that upper tail, and it's a z value, and we would reject the null.
00:45
If we are above, and let's look at 5%, it's going to be that 1 .645, pretty sure.
00:51
Yep, 1 .645.
00:53
So if we are higher than that value for our test statistic, we're going to reject the null.
00:58
Now part b wants us to find that pooled p, which they labeled p sub c.
01:03
And so our pooled p is to sum up these two, 70 plus 90, and then 100 plus 150.
01:12
And i can write, apparently not very well, 150.
01:18
There we go.
01:19
So we get 160 out of 250, and that proportion comes out to be as a decimal, as this one is naturally 0 .7, and this one is 0 .6, and this pooled p is 0 .64.
01:38
So part c, we need to figure out what our test statistic is.
01:42
So we're going to take the difference between our two proportions, 0 .7 minus 0 .6...