the-number-n-of-dollars-saved-by-increasing-the-fuel-efficiency-of-e-milgal-to-e6-milgal-for-a-car-d

Name: the number n of dollars saved by increasing the fuel efficiency of e milgal to e6 milgal for a car d
Uploaded: 2020-08-20
Duration: 2 min 31 s
Channel: Numerade
Description: The number $n$ of dollars saved by increasing the fuel efficiency of $e$ milgal to $e+6$ milgal for a car driven 10,000 milyear is $n=\frac{195,000}{e(e+6)},$ if the cost of gas is $\$ 3.25 /$ gal. Sketch the graph.

Question

The number $n$ of dollars saved by increasing the fuel efficiency of $e$ milgal to $e+6$ milgal for a car driven 10,000 milyear is $n=\frac{195,000}{e(e+6)},$ if the cost of gas is $\$ 3.25 /$ gal. Sketch the graph.

Ankit Gupta · Accepted Answer

it is given that decoration F is equal to B minus 0.191 as scale plus 1.639 s plus 2.20 where the value off s is Berries from 5 to 65. There s represent the average speed off the car and every presented the fuel efficiency. Now we need to plot the graph off the given model. The graph we look like s the maximum value photograph is lies here. Now, this is the point where the value of speed off the car is 42.906 and the fuel efficiency is 37.361 So maximum fuel efficiencies 37.361 when the speed off the car is 42.2906 My but no. Now we need to find the efficiency fuel efficiency, increasing factor when the every speed of the car is increased from 20 MPH 2 30 miles. But so put the value of as is equal to be 20 miles, but are in the given a question we get the value of F is equal to B minus 0.191 20 Scared plus 1.639 while deployed with 20 plus 2.20 Now I simply find it gets the value off. Fuel efficiency is equal to between 37.34 Now put the value off s is equal, Toby 30 miles, but are in the given question. We get, we get the value off. F is equal to B minus zero point 0191 30 scale plus 1.639 multiplied with 30 plus 2.20 Now they simply find it. We get the value off F physical. Toby 34.18 now 34.18 is 1.25 times off the 27.34 So efficiency, fuel efficient, single easing factor is 1.25 So this is a world answer.

Stephen Russell · Answer

in this example. Let&#x27;s first start with what we know. We know that the price of gas is $2.34 per gallon. Uh, in this question, they&#x27;re asking us to complete the table. So let&#x27;s start with the taxes. The taxes for this amount for gas is 18%. The distribution or marketing is 10% the refining is 11% and the crude oil is 61% of that price. So to figure out how much money is going towards taxes, we&#x27;re gonna find 18% of $2.34. That equation looks like n equals 0.18 times 2.34 And this gives us a value of a little bit more than 42 cents for the distribution or marketing. We have a similar equation. It will be an equals 0.10 times 2.34 which gives us a value of a little bit more than 23 cents. For the refining, we have and equals 0.11 times 2.34 which gives us a amount of a little bit more than 25 cents. And for the crude oil amount, we have an equation of n equals 0.61 times 2.34 which gives us an amount of $1 and you know a little bit more than 42 cents of that dollar.

Stephen Russell · Answer

in this example, we&#x27;ve been given the price of gas per accountant at $2.73. Uh, we&#x27;re being asked to complete the table for these various, um, pieces of what we pay for in a gallon of regular gasoline. We have taxes, distribution or marketing. We have refining, and we in crude oil taxes make up 15% of our cost distribution, and marketing makes up 10% refining 9% and crude oil is 66%. In order to figure out how much money each one of these percentages represents of R two r, $2.74 let&#x27;s set up the equations for each, for taxes will have n equals 0.15 That&#x27;s our percentage times the price of our guests, um, in this value is a little bit more than 41 cents. The distribution or marketing is a similar equation and equals 0.10 times $2.73. This value is a little bit more than 27 cents. Refining at 9% n equals 0.9 times 2.73 which is a value a little bit more than 24 cents and crude oil, at 66% is an equals 0.66 times 2.73 which is a value of $1 a little bit more than 80 cents.

Amy Jiang · Answer

Okay, so this time we went to graph the data under a table. So this insert or chart here and this should be a straight line. So this here is our God.

Ankit Gupta · Answer

So in this question, if I observed carefully, I have to find a envy so that it off x equal to explore, be immortals. The date exactly. So if I write f of x equal toe explodes be, I&#x27;ll put random values. First of all, 115 is equal to five plus b Next wonder 30 z caldo, then there plus B. So if I call this in Question one. And if I call this as a question, too, when I subtract this I love when 15 is equal to five, all of this I&#x27;m grating by doing the question to minus the question one. So from here I love is a photo 23 on substituting this putting Any question one I allow 115 is 1/4 23 in tow, five plus B. So from here on, said B is equal to zero. So that is a values off A and B let so that love of process still data point in their table. All right, now, in the next part interpreted the slope off graphic. So if I talk about slope, Slope is equal to y tu minus y one. So I&#x27;ll write it US 115 minus 230 Be right away. Five minus 10. So I can write it. US minus 115 divided WiFi. So I can say Slope M is a caldo minus five on minus 115 So that is equal to 23. Next part. How many miles could be driven using particulates of gasoline. So here I have the data 10 12 and 16. So for this I have to find out the affects relation that waas X plus B and we found, or this one This is nothing but 23 x and be 10 So F 20 will be called 23 20. So that is a photo 460 miles. So that&#x27;s where to be. So that&#x27;s going to be there. Distance that can be driven using 20 gallons of gasoline. I over. It&#x27;s clear. Thank you.

Problem

The reliability $R$ of a computer model is found …

Problem 26 Easy Difficulty

The number $n$ of dollars saved by increasing the fuel efficiency of $e$ milgal to $e+6$ milgal for a car driven 10,000 milyear is $n=\frac{195,000}{e(e+6)},$ if the cost of gas is $\$ 3.25 /$ gal. Sketch the graph.

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Allyn J. Washington, Richard S. Evans

Basic Technical Mathematics with Calculus

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Allyn J. Washington, Richard S. EvansBasic Technical Mathematics with Calculus

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Allyn J. Washington, Richard S. Evans

Basic Technical Mathematics with Calculus