00:01
Formula to find the number of diagonals and a polygon with n sides.
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So d is the number of diagonals and is the number of sides.
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So in part a, we want to determine the number of side a polygon with 464 diagonals will have.
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So we'll start by substituting 464 and for d.
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So at 464 equal to n over 2 times n minus 3.
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And now we just need to solve for n.
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So the first thing we're going to do is distribute the n over 2.
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Well, n over 2 times n is n squared over 2.
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2, and n over 2 times negative 3 is negative 3 over 2n.
00:35
Now, let's go ahead and get rid of our fractions.
00:38
To do this, we're going to multiply each side of our equation by 2.
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Well, 2 times 464 is equal to 928.
00:47
2 times n squared over 2 is just n squared, and 2 times negative 3 over 2 is negative 3.
00:55
So now i see we have a quadratic equation, so we're going to set this equal to 0.
00:59
So i'll subtract both sides by 928.
01:02
So we'll have 0 equal to n squared minus 3n minus 928.
01:08
So now i'm going to solve this by factoring.
01:11
Because our leading term has a coefficient of 1, i'm going to set up our two factors, both of which start with n because n times n is n squared.
01:19
So now we just have to find two numbers that multiply the negative 928 that will add to negative 3.
01:26
So in this case, i'm going to use negative 32 and positive 29.
01:31
So let's substitute those in.
01:32
So we have negative 32 plus 29.
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And now that we have our two factors, we set them equal to zero.
01:39
So n minus 32 could be equal to zero or n plus 29 could equal to zero.
01:45
And now we solve both equations.
01:46
So we'll add 32 to both sides to solve the first.
01:49
So n could equal to 32...