Question
The number of enantiomers of the compound $\mathrm{CH}_{3} \mathrm{CHBrCHBrCOOH}$ is(a) 1(b) 2(c) 3(d) 4
Step 1
A chiral center is a carbon atom that is bonded to four different groups. In this case, we have two chiral centers: the second carbon (C2) bonded to a hydrogen, a methyl group, a bromine, and the third carbon; and the third carbon (C3) bonded to a hydrogen, a Show more…
Show all steps
Your feedback will help us improve your experience
Dr. Satish Ingale and 93 other Organic Chemistry educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The number of stereoisomers formed by the compound is: (a) 1 (b) 2 (c) 3 (d) 4
The number of chiral carbon atoms in the given compound is are (a) 2 (b) 3 (c) 4 (d) 1
The number of stereoisomers obtained by bromination of trans-2-butene is (a) 1 (b) 2 (c) 3 (d) 4
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD