00:02
In this problem it is given that the number of errors in a textbook follows a poison distribution with a mean of 0 .01 error per page.
00:13
Let x denote the number of errors in one page.
00:17
So we have lambda is equal to 0 .01.
00:24
It is asked what is the probability that there are three or less errors in 100 pages? as we have to find the probability for 100 pages, t is equal to 100.
00:39
And so, lambda t is 0 .01 into 100 which is equal to 1.
00:46
We know that for a poison random variable x, probability of x equal to x is e raised to minus lambda t into lambda t raised to x divided by x factorial, where x ranges from 0, 1, 2 up to infinity.
01:03
So this is equal to e raised to minus 1 into 1 raised 2x divided by x factorial.
01:17
But we know that 1 raise to x is always 1.
01:22
So this is equal to e raised to minus 1 into 1 that is e raised to minus 1 divided by x factorial...