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The number of feet that a car travels before stopping depends on the driver's reaction time and the braking distance, as shown below. For one driver, the stopping distance $d$ is given by the equation $d=0.04 v^{2}+0.9 v$ where $v$ is the velocity (speed) of the car. Find the stopping distance when the driver is traveling at $30 \mathrm{mph}$ (FIGURE CAN'T COY)

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$63 \mathrm{ft}$

Algebra

Chapter 10

Exponents and Polynomials

Section 2

Introduction to Polynomials

Polynomials

Missouri State University

University of Michigan - Ann Arbor

Idaho State University

Lectures

01:05

Stopping Distance. The num…

01:15

The number of feet that a …

01:14

Stopping Distances. The nu…

00:24

The stopping distance of a…

00:27

00:30

00:41

0:00

Stopping Distance When the…

02:16

03:16

For a certain stretch of r…

all right. Our equation is Dean equals 0.0 for these. Weird what? Zero point nine. Okay. And we're running in 34 v equals 30. So I have 0.0 or times 30 squared, plus Wait. Nine times 30. So 30 square is 900 0.9 times three is 27. So I have move the desk for one. So I have to 77. 27 30 times 0.9. The road to seven. One. That's more over. Just 27 now. Take 900 times 9000.4 009 times four is 36. May have two decimal places. 12 So this is 36. Well, 27 which gives me 63 that is in be

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