Question
The number of geometrical isomers of$\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CHCl}$ are(a) 4(b) 6(c) 8(d) 10
Step 1
There are two possibilities for each double bond: cis (Z) and trans (E). Now, let's count the number of geometrical isomers for the given compound. There are three double bonds, so we have 2 possibilities for each double bond, which gives us a total of 2^3 = 8 Show more…
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The number of geometrical isomers of $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CHCl}$ is (a) 4 (b) 6 (c) 8 (d) 10
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