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Hello.
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So for part a here, we're going to be substituting 3 into p of t.
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So we're doing p of 3.
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So p of 3 is going to be negative 8 times 3 squared and then plus 52 times 3 and then plus 150.
00:22
So that is going to evaluate to negative 72 plus 156 plus 150.
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So that is going to evaluate to negative 72 plus 156 plus 150.
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150, which is going to be equal to 234.
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So for part a, we have 234 products, and that is per hour.
00:40
And then for b, the damaged products after three hours, now we're substituting t equals 3 into d of t.
00:48
So we're doing d of 3.
00:50
So d of 3 is going to be equal to negative 0 .5 times 3 squared, plus 3 times 3, plus 3, plus...