Question
The number of real roots of the equation $x^{3}-\frac{1}{x^{3}}+4\left(x-\frac{1}{x}\right)=0, x \neq 0$(a) 3(b) 0(c) 1(d) 2
Step 1
We can rewrite $x^{3}-\frac{1}{x^{3}}$ as $x^{3}-\frac{1}{x^{3}} = (x-\frac{1}{x})^{3}+3(x-\frac{1}{x})$ using the formula for the difference of cubes $a^{3}-b^{3} = (a-b)(a^{2}+ab+b^{2})$. Show more…
Show all steps
Your feedback will help us improve your experience
Anas Venkitta and 77 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The number of real roots of the equation $(x-1)^{2}+(x-2)^{2}+(x-3)^{2}=0$ is (a) 2 (b) 1 (c) 0 (d) 3
Number of real roots of the equation $\left|x^{2}+x-6\right|+2|x|-4=0$ is (a) 0 (b) 1 (c) 2 (d) 3
How many roots does the equation $\frac{2}{x^{2}}+\frac{1}{x}=0$ have? $$ \begin{array}{llll}{\text { A. } 0} & {\text { B. } 1} & {\text { C. } 2} & {\text { D. } 3}\end{array} $$
Rational Functions
Solving Rational Equations
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD