00:01
Okay, so for the next question, we are given a quadratic expression, which also contains something in the mode.
00:06
Okay, that is x minus 1 square minus 5 times of mode x minus 1 plus 6 equals to 0.
00:15
Okay, so whenever we see the mode, we have to find out the critical points and we have to make cases upon the critical points.
00:21
Okay, so the critical point here i can see is 1.
00:26
So i'll make the case, first case is x greater than 1.
00:30
Greater than equals to let's say.
00:32
So the expression, the quadratic expression becomes x squared plus 1 minus 2x, minus 5x, plus 5 plus 6 equals to 0.
00:45
Okay, so the final equation comes out to be this.
00:50
Okay, and the roots will be, if we split it up, it becomes x minus 4, x minus 3 is equals to 0.
00:57
Which implies, here from here we have xx's values are the 3 and 4.
01:01
We got the values of x as 3 and 4...