The number of ways of choosing $N_{1}$ items from a collection of $N>N_{1}$ items without respect to ordering is
$$
W=\frac{N !}{N_{1} ! N_{2} !}
$$
where $N_{2}=N-N_{1}$. Calculate $\ln W$, making use of Stirling's approximation $\ln n ! \simeq n \ln n-n$, which is very accurate for large $n .$ Express your result in terms of $N$ and $x \equiv N_{1} / N$, and compare with equation $(9.14)$.