00:01
Okay, this problem is asking us to draw the last stages of the mechanism of the iotaform test.
00:06
So it is stated that we are given tri -iodo -methyl ketone, which looks like this, where we have three iodines connected to my ketone.
00:16
Okay, and this is going to react with sodium hydroxide, n -i -o -h.
00:21
So sodium hydroxide, we know it to be a very strong base, and sometimes a nucleophile.
00:26
In this case, it is going to act as a nucleophile, and that is because, through resonance, this carbonene...
00:31
Is pulling electron density away from this carbon.
00:35
And with the presence of these iodines, it is pulling electron density away through the inductive effect.
00:40
Okay, so we have very small amount of electron density on this carbon, resulting in an electrophilic carbon.
00:47
So that is why my hydroxide ion can come in and act as a nucleophile and attack that carbon.
00:53
So when it does that, it's going to move the electrons away from that double bond and onto my oxygen, resulting in this compound, where i have my tetrahedron.
01:01
Intermediate, i have my newly added alcohol, and my carbon connected to three iodides...