00:02
Hello guys, so problem for t4.
00:07
The orbits of earth are dwarf planets curves eat out to a maximum distance of 97 .7 au from the sun.
00:16
Assuming an orbital of 0 .8, what is the average temperature of earth when it's as farthest from the sun? so we have the albedo to be 0 .8.
00:30
The distance of errors of errors rather to be 97 .7 .7.
00:46
So we have 97 .7 a.
00:56
And the question is actually not as to find the average temperature of earth when it says farthest from the sun.
01:02
So we are to find the temperature.
01:09
Yeah.
01:10
So using the information given from the question, we're going to be using the formula for calculating the temperature of a planet, a certain distance from the sun watches t is equal to 279, 279 multiplied by brackets 1 minus a divided by d, e, the distance of the planet, or in this case the distance of errors from the sun, 1 divided by 4.
01:56
A stands for the orbital of earth and e stands for the distance of earth to the sun.
02:03
And so inputting that into both this is actually 279 kelvin.
02:10
So inputting the values we have into this equation, we have 279, 279 multiplied by the albedo of eris, which is 0 .8.
02:40
0 .8 divided by 97 .97 .7...