Question
The orbit of the Moon about the Earth is approximately circular, with a mean radius of $3.84 \times 10^{8} \mathrm{~m}$. It takes $27.3$ days for the Moon to complete one revolution about the Earth. Find (a) the mean orbital speed of the Moon and (b) its centripetal acceleration.
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84 \times 10^{8} \mathrm{~m}$ and it takes $27.3$ days for the Moon to complete one revolution about the Earth. We are asked to find the mean orbital speed of the Moon. The mean orbital speed is given by the formula $v = \frac{d}{t}$, where $d$ is the distance Show more…
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Find the centripetal acceleration of the moon toward the earth, assuming that the orbit of the moon is a circle of neclius 239,000 miles $=3.85 \cdot 10^{8} \mathrm{m},$ and the time for one complete revolution is 27.3 days $=2.36 \cdot 10^{6} \mathrm{sec}$
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The Moon revolves around Earth in a circular orbit with a radius of 3.84x10^8 m. It takes 27.3 days for the Moon to complete one orbit around Earth. What is the centripetal acceleration of the Moon?
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