Question
The orbiting Chandra X-ray telescope, observing at about $0.1 \mathrm{nm},$ can collect about $2 \times 10^{-13}$ watts (joules per second) of radiation from the Crab Nebula. About how many photons is it collecting each second?
Step 1
We can use the formula: E = (hc) / λ where E is the energy of the photon, h is the Planck's constant (6.63 × 10^-34 Js), c is the speed of light (3 × 10^8 m/s), and λ is the wavelength (0.1 nm or 1 × 10^-10 m). E = (6.63 × 10^-34 Js × 3 × 10^8 m/s) / (1 × Show more…
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