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Question.
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We have two atoms, and one has an effective nuclear charge of plus two, and the distance of 225 picometers between the balanced electron and the nucleus.
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For atom b, we have an effective nuclear charge of plus one, and the average distance between the outermost valence electron and the nucleus 175.
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We want to know which one has the highest first ionization energy.
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So what we are going to do is we are going to use coulom's law in order to determine this.
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So coulom's law can be written like this.
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So if we multiply both sides by r, we get force times distance.
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So force times distance is equal to work done, which is equal to potential energy.
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So we can write the following.
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So from this, we can use this to calculate the potential energy between the two charges in these atoms.
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The charge of an electron and proton is going to be 1 .6 times 10 to the negative 19 coolums.
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So we only need to care about the absolute value in this case, because we're only looking at the value of the potential energy.
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In both cases, it will actually be negative, and i've explained that here.
01:41
But for simplification purposes, we actually would just need to look at the absolute value.
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So we have an effect nuclear charge of two.
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So let's multiply the charge of one proton by two, and we get the charge in coolums that we experience from, that the electron experiences in atom a.
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So let's do this calculation for atom a.
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So we plug in the values into the formula...