The overall change in the radioactive decay of ${238}_{92} \mathrm{U}$to 206 $\mathrm{Pb}$ is the emission of eight $\alpha$ particles. Show that if $_{82}^{206} \mathrm{Pb}$this loss of eight $\alpha$ particles were not also accompanied by six $\beta^{-}$ emissions, the product nucleus would still be radioactive.