The oxidation of $\mathrm{NO}$ (released in small amounts in the exhaust of automobiles) produces the brownish-red gas $\mathrm{NO}_{2}$, which is a component of urban air pollution.
$$2 \mathrm{NO}+\mathrm{O}_{2} \longrightarrow 2 \mathrm{NO}_{2}$$
The rate law for the reaction is rate $=k[\mathrm{NO}]^{2}\left[\mathrm{O}_{2}\right] . \mathrm{At}$ $25^{\circ} \mathrm{C}, k=7.1 \times 10^{9} \mathrm{~L}^{2} \mathrm{~mol}^{-2} \mathrm{~s}^{-1}$. What would be the
rate of the reaction if $[\mathrm{NO}]=0.0010 \mathrm{~mol} \mathrm{~L}^{-1}$ and $\left[\mathrm{O}_{2}\right]$
$=0.034 \mathrm{~mol} \mathrm{~L}^{-1} ?$