00:01
This is a great problem to understand the behavior of gases because this allows us to investigate a real -world application like the ozone layer.
00:11
So this is a very quick visualization of the information in the problem.
00:16
We have this ozone layer and we know that this ozone layer is 20 kilometers thick.
00:23
We're also told that our temperature is 230 kelvin.
00:27
We know that our total pressure is 1 .3 times 10 to the negative.
00:31
Of second atm.
00:34
And we're going to say let lambda be area.
00:37
If lambda is confusing, you just think of it as a variable.
00:41
It's nothing different.
00:43
We're going to say let lambda be area.
00:46
So we can say that our volume will be equivalent to 20 times lambda.
00:50
Remember, lambda is area.
00:53
We should know this equation where the p total, pressure total, times v total, our volume, is equivalent to our n total, the number of moles times rt.
01:06
Now we can plug things in that we know to this equation.
01:10
Define n total, n total or our number of moles, will be equivalent to 1 .3 times 10 to the negative second times 20 lambda divided by 0 .0821 times 230.
01:25
This will simplify, so our number of total moles is 0 .0136 times lambda.
01:35
Now what we can do is we can find the mole fraction of ozone, which is 03.
01:40
The mole fraction of ozone will be equivalent to the moles of ozone divided by our total number of moles.
01:49
And if we rearrange this equation or make a substitution, we should know that the moles or pardon me, the mole fraction of ozone is equivalent to the pressure of ozone divided by the total pressure...