Question
The parametric equation of a point on the circle $x^{2}+y^{2}-8 x-6 y+16=0$ is(a) $(4+3 \cos \theta, 3+3 \sin \theta)$(b) $(3 \cos \theta-4,3 \sin \theta-3)$(c) $(2+3 \cos \theta, 3+2 \sin \theta)$(d) $(4+9 \cos \theta, 3+9 \sin \theta)$
Step 1
We can rewrite this equation in the form $(x-a)^{2}+(y-b)^{2}=r^{2}$, where $(a,b)$ is the center of the circle and $r$ is the radius. Show more…
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