00:01
In this problem, we have to calculate the change in period of the pendulum when the nut is moved upward.
00:08
So we have to calculate delta t.
00:12
Let's write the equation for the period of the pendulum as t1 is equal to 2 pi square root of l1 divided by g.
00:24
Here this l1 is the length of the pendulum and g is the gravitational acceleration.
00:29
So this will be our equation number one.
00:31
Similarly, we can write the period 2 when the pendulum is moved upward, so it will be t2 and this is equal to 2 pi square root of l2 divided by g.
00:46
And this can be written as 2 pi square root of l2 which is equal to l1 minus h divided by g.
00:56
So this will be our equation number 2.
01:02
Now using equation number 1 and equation number 2, we can write here.
01:05
Delta t as delta t is equal to t2 minus t1 so this is equals to 2 pi divided by square root of g into square root of l1 minus square root of l1 minus h so this will be our equation number three let's set the values into this quadrant so this can be written as delta t is equal to 2 into 3 .14 divided by square root of 9 .80 meter per second square...