00:01
For this problem, we are told that the percentage of people age 12 years and older using social network sites and or services several times a day from 2009 to 2013 grew at the rate of r of t equals 5 .92 t to the power of negative 0 .168 for t between 1 and 5, with t equaling 1 corresponding to 2009.
00:22
The percentage of people age 12 years and older using social network sites and or services is 2 in 2009 was 7%.
00:30
For part a, we are asked to find an expression giving the percentage of people age 12 years and older using social network sites and or services in year t for t between 1 and 5.
00:40
Man, that was a lot of words.
00:42
All right, so, p of t for, let's say, percentage, is going to be the anti -derivative of r of t.
00:48
That's going to be 5 .92 times now the antiderivative of t to the power of negative 0 .168 is going to be t to the power of 1 minus 0 .168, or negative 0 .168, or negative 0 .0 .0.
01:00
0 .168 plus 1, divided by 1 minus 0 .168.
01:08
For part b, actually, i'm not going to be lazy.
01:11
One second here.
01:13
All right, so evaluating that out or simplifying it down a little bit, we get that it's going to be approximately 7 .11 times t to the power of 0 .832.
01:25
All right.
01:26
For part b, we are asked, according to the model, what percentage, blah, blah, blah, blah, blah, in 2013...