00:02
In this problem, we're given a rectangle, and we're told that the perimeter of the certain rectangle, p, being the perimeter, is equal to 101 .74 centimeters.
00:14
We're also told that the length of the rectangle is 4 .25 centimeters longer than the width.
00:21
So if i have width, w, weights w, i know that the length is equal to w plus an additional 4 .2.
00:37
0 .25 centimeters longer.
00:41
Our goal is to find what is w and what is l, the dimensions of the rectangle.
00:49
So i can set the perimeter of 101 .74 centimeters equal to the sum of the four sides, which would be equal to 2 times the width plus 2 times the length being w plus 4 .25.
01:11
Or 101 .74 is equal to 2w plus 2w plus 2 times 4 .25 is 8 .5.
01:27
We're going to combine light terms, the ws, and subtract 8 .5 from both sides of the equation...