Question
The perimeter, $P,$ of a rectangle is $P=2 l+2 w$ where $l=$ length and $w=$ width.a) Solve $P=2 l+2 w$ for $w$.b) Find the width of the rectangle with perimeter $28 \mathrm{~cm}$ and length $11 \mathrm{~cm}$.
Step 1
To do this, we subtract $2l$ from both sides of the equation to isolate $w$ on one side. This gives us $P-2l=2w$. Show more…
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