00:01
The concentration of hydrogen ion can be calculated as using the ph formula.
00:08
Ph is equal to negative log of concentration of hydrogen positive ions.
00:14
Substituting in the values, we have 6 .3 for ph equals negative log for hydrogen positive.
00:24
Taking an antelog, the concentration of hydrogen positive iron turns to 5 .01, 10 raised to 1, negative.
00:33
7 molar.
00:37
In the question, we are already provided with the equilibrium of various phosphate salts.
00:44
So let me write them again.
00:46
We have for h3, p .o4, the equilibrium k1 will be equal to 7 .5, 10 raised to 1 negative 3.
00:59
For second salt, k2 will be equal to 6 .2, 10 raised to 1 negative 8.
01:11
For the third 1 ,000, h .p .o .4 to negative, k3 will be equal to 3 .6, 10 raised to 1 negative 13.
01:28
We know the dissociation constant for k3 can be written as h3 o positive and p .o .3 -9, divided by hpo4 -2 negative, substituting in the value.
01:55
We are rearranging and substitution the values again.
02:00
So the concentration of h.
02:05
P .o4 to negative will be equal to 5 .01, 10 raised to to power negative 7 divided by 3 .6, 10 raise to power 6, and concentration for p .o .4, 3 negative...