00:01
Standard cell potential, that is e0 cell, is given by e .0, cathode, that is the standard cell potential at cathode minus e .0.
00:10
Enode, that is, standard cell potential at anode.
00:14
So now at anode.
00:16
Well, we have to identify which of the following reactions are acting on anode and which reaction is acting at cathode.
00:23
So, at anode, h2 leads to formation of h -positive ion.
00:32
By releasing two electrons.
00:34
Okay, so this is what? this is oxidation.
00:36
Always remember, oxidation takes place at anode.
00:41
And at cathode, m4 positive ion.
00:52
So this gains two electrons to form m2 positive iron.
00:57
So this is reduction, gaining of electron.
01:04
So now, the overall reaction will be h2 plus m4, positive so this will give 2h positive ion plus m2 positive ion so now e0 cell is we have we have calculated the e0 cell now we will calculate the e -cell that is the emf of the cell so emf of the cell is given by an earnest equation and nullnest equation says that e0 cell minus 0 0 0 0 0 0 0 .0 059 divided by now divided by n right log the oxidized species divided by reduced species okay now see here e0 cell is what 0 .151 okay how so because e0 cell is equal to e cathode minus e anode right we have written it above...