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The phasor diagram for an RLC circuit is shown in FlGURE $24-38$ . (a) If the resistance in this circuitis $525 \Omega,$ what is the impedance? (b) If the frequency in this circuit is increased, will the impedance increase, or stay the same? Explain.
a) 606 ohmsb) see explanation
Physics 102 Electricity and Magnetism
Chapter 24
Alternating-Current Circuits
Current, Resistance, and Electromotive Force
Direct-Current Circuits
Electromagnetic Induction
Alternating Current
University of Washington
Simon Fraser University
Hope College
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in the first item. We just have to remember that the co sign off the phase is he goes true. The resistance divided by the impedance and then the impedance is because to the resistance divided by the co sign off the phase, the resistance is 5 to 5 homes. Onda face is 30 degrees, so we have the cool sign off 30 degrees and these is equals 25 25 divided by the square it off three divided by two. These gives approximately 600 seeks owns off impedance. For the second item, we can remember off the following the tangent off the phase is equals two Accel Miners XY divided by the resistance. The phase in these questions is equal to 30 degrees and the tangent off 30 degrees is bigger than zero. Therefore, excel in this circuit is already bigger than exceed. Now remember, the following Excel is equal to the frequency times. They look tense on daxi musicals to a world divided by the frequency times the capacitance. By increasing the frequency, we are increasing excel while decreasing exceed. Therefore, what happens is that the quantity excel miners XY as a wall, you increase then remember that impudence is It goes to the square it off r squared. Nothing happens in the resistance as we mass with the frequency plus Excel miners XY squared. We have seen that by increasing the frequency, we are increasing this term here. Therefore, by increasing the frequency in this particular sirrah quite that particular set up. We are also increasing the impudence.
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