00:01
In this question, we are looking at dice throwing as a way of simulating radioactive decay.
00:09
A dye we know has six sides, right? six sides.
00:16
And so for any site, there's no particular preference for the dice to go into any of these sites when you throw them.
00:27
And so when we choose, say, number one, to represent.
00:32
That the nucleus has decayed, you're choosing one of six of all equal sides, right? so the probability that the dice would decay is equal to the probability that the dice would land on any number, right? so the probability of the dice landing on number one is simply one of six because there are six numbers with equal chance of getting, getting that number.
01:10
Right so the average number of dice you expect to decay.
01:15
Since this is the decay probability we can just multiply n with the probability where n is the number of die at a start, right? okay now for the next part you want to find what is the average number of dice that is undecade after three tosses.
01:50
Well the probability of not landing on one would be the probability of not decaying, right? and the chances of that is five of six because there are five other numbers which are not one...