The inner diameter of the pipe is given as \( d = 2 \, \text{in} \). The wall thickness is \( t = 0.15 \, \text{in} \).
The outer diameter \( D \) can be calculated as:
\[
D = d + 2t = 2 \, \text{in} + 2(0.15 \, \text{in}) = 2.3 \, \text{in}
\]
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