Question
The plate $R$ in Figure $8,$ bounded by the parabola $y=x^{2}$ and $y=1,$ is submerged vertically in water (distance in meters).$$\begin{array}{c}{\text { (a) Show that the width of } R \text { at height } y \text { is } f(y)=2 \sqrt{y} \text { and the fluid }} \\ {\text { force on a side of a horizontal strip of thickness } \Delta y \text { at height } y \text { is }} \\ {\text { approximately }(\rho g) 2 y^{1 / 2}(1-y) \Delta y .} \\ {\text { (b) Write a Riemann sum that approximates the fluid force } F \text { on a side }} \\ {\text { of } R \text { and use it to explain why }} \\ {F=\rho g \int_{0}^{1} 2 y^{1 / 2}(1-y) d y} \\ {\text { (c) Calculate } F .}\end{array}$$
Step 1
The plate extends from point $(-\sqrt{y}, y)$ on the left to the point $(\sqrt{y}, y)$ on the right. Therefore, the width of the plate is given by $f(y)$ which is equal to $\sqrt{y} - (-\sqrt{y}) = 2\sqrt{y}$. Show more…
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A plate in the shape of an isosceles triangle with base 1 $\mathrm{m}$ and height 2 $\mathrm{m}$ is submerged vertically in a tank of water so that its vertex touches the surface of the water (Figure 7$)$ $$ \begin{array}{l}{\text { (a) Show that the width of the triangle at depth } y \text { is } f(y)=\frac{1}{2} y \text { . }} \\ {\text { (b) Consider a thin strip of thickness } \Delta y \text { at depth } y . \text { Explain why the }} \\ {\text { fluid force on a side of this strip is approximately equal to } \rho g \frac{1}{2} y^{2} \Delta y}\\{\text { (c) Write an approximation for the total fluid force } F \text { on a side of the }} \\ {\text { plate as a Riemann sum and indicate the integral to which it converges. }} \\ {\text { (d) Calculate } F .}\end{array} $$
FURTHER APPLICATIONS OF THE INTEGRAL AND TAYLOR POLYNOMIALS
Fluid Pressure and Force
The plate, bounded by the parabola y = x^2 and y = 49, is submerged vertically in water (distance in meters). Calculate the fluid force F on a side of the plate. The acceleration due to gravity is 9.8 m/s^2. The density of water is 1000 kg/m^3. (Give an exact answer: Use symbolic notation and fractions where needed) F = N
Let $F$ be the fluid force on a side of a semicircular plate of radius $r$ meters, submerged vertically in water so that its diameter is level with the water's surface (Figure 9). $$ \begin{array}{l}{\text { (a) Show that the width of the plate at depth } y \text { is } 2 \sqrt{r^{2}-y^{2}}} \\ {\text { (b) Calculate } F \text { as a function of } r \text { using Eq. }(2) .}\end{array} $$
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