Question
The plates of a $15.0 \mu F$ capacitor have net charges of $+0.75 \mu \mathrm{C}$ and $-0.75 \mu \mathrm{C},$ respectively.(a) What is the potential difference between the plates?(b) Which plate is at the higher potential?
Step 1
We are given the capacitance (C = 15.0 μF) and the charge on the plates (Q = 0.75 μC). We can rearrange the formula to solve for the potential difference: V = Q / C Plugging in the given values: V = (0.75 μC) / (15.0 μF) = 0.05 kV = 50 V So the potential Show more…
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