00:01
So in this problem we have a capacitor and from the problem we know the parameters the separation d is 2 .5 millimeters and so charge on the capacity is 80 nanoculombs and the electric field is four times so this is a charge equal 80 nanoculums and the electric field inside is four times ten to the six.
00:33
Volt per meter, okay? excuse me.
00:39
So in part a, we want to figure out the potential difference between the two plates because the electric field inside the two plates is uniform.
00:49
So in that sense, the potential difference e, v, equal e times d.
00:54
So here is the electric field, and this is the separation.
00:58
So you'll see that this equal 10 to this 4 volts, okay.
01:03
And in part b, we want to figure out the, area of this capacity.
01:11
So we already have the potential difference of the two plates, and we have expression q equals c times v, right? so v is given here, and the q is 80 nanoculums...